3x^2+2x-72=8x

Solution for 3x^2+2x-72=8x equation:

3x^2+2x-72=8x

We move all terms to the left:

3x^2+2x-72-(8x)=0

We add all the numbers together, and all the variables

3x^2-6x-72=0

a = 3; b = -6; c = -72;
Δ = b2-4ac
Δ = -62-4·3·(-72)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-30}{2*3}=\frac{-24}{6}
=-4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+30}{2*3}=\frac{36}{6}
=6
$